pliss tolong bantuin
1. f (x) = x²-2x+3
g (x) = 2x-1
*(f°g) (x) =
*(g°f) (x) =![]()
1. f (x) = x²-2x+3
g (x) = 2x-1
*(f°g) (x) =
*(g°f) (x) =
Jawaban:
diketahui:
f(x) = {x}^{2} - 2x + 3f(x)=x2−2x+3
g(x) = 2x - 1g(x)=2x−1
ditanya:
(fog)(x)= ...
(fog)(x)= f(g(x))
fungsi gx dimasukan ke fx
(fog)(x) = (2x - 1)^{2} - 2(2x - 1) + 3(fog)(x)=(2x−1)2−2(2x−1)+3
= 4x^{2} - 4x + 1 - 4x + 2 + 3=4x2−4x+1−4x+2+3
= 4 {x}^{2} - 8x + 6=4x2−8x+6
